ਖੋਜ ਨਤੀਜੇ

_{n}}^{\mu _{1}\nu _{1}...\mu _{n}\nu _{n}}=n!\delta _{\lbrack \alpha _{1}}^{\mu _{1}}\delta _{\beta _{1}}^{\nu _{1}}\cdots \delta _{\alpha _{n}}^{\mu _{n}}\delta...

{\displaystyle D_{\mu }=\partial _{\mu }+{\frac {1}{2}}\Omega _{\mu }} D μ = ∂ μ + Ω μ × , {\displaystyle {\mathcal {D}}_{\mu }=\partial _{\mu }+\Omega _{\mu }\times...

-{\frac {1}{c^{2}}}{\frac {\partial ^{2}\mathbf {A} }{\partial t^{2}}}&=-\mu _{0}\mathbf {J} \end{aligned}}} ਹੋਰ ਗੇਜਾਂ ਵਿੱਚ ਇਕੁਏਸ਼ਨਾਂ ਵੱਖਰੀਆਂ ਹੁੰਦੀਆਂ ਹਨ।...

c 4 T μ ν {\displaystyle G_{\mu \nu }\equiv R_{\mu \nu }-{\textstyle 1 \over 2}R\,g_{\mu \nu }={8\pi G \over c^{4}}T_{\mu \nu }\,} ਖੱਬੇ ਪਾਸੇ ਆਈਨਸਟਾਈਨ ਟੈਂਸਰ...

\end{aligned}}} ਜਿੱਥੇ v p h = 1 μ ε {\displaystyle v_{ph}={\frac {1}{\sqrt {\mu \varepsilon }}}} ਪ੍ਰਕਾਸ਼ ਦੀ ਸਪੀਡ ਹੈ (ਯਾਨਿ ਕਿ, [[ਪਰਮਿਬਲਿਟੀ (ਇਲੈਕਟ੍ਰੋਮੈਗਨਟਿਜ਼ਮ)|ਪਰਮਿਬਲਿਟੀ...

2 μ ∇ 2 ψ − e 2 4 π ε 0 r ψ {\displaystyle E\psi =-{\frac {\hbar ^{2}}{2\mu }}\nabla ^{2}\psi -{\frac {e^{2}}{4\pi \varepsilon _{0}r}}\psi } ਜਿੱਥੇ; e...

{\frac {\partial }{\partial x^{\mu }}}\left[{\frac {\partial {\mathcal {L}}}{\partial (\partial \phi /\partial x^{\mu })}}\right]-{\frac {\partial {\mathcal...

review and survey, including hundreds of references.) Cheeger, Jeff; Ebin, David G. (2008), Comparison theorems in Riemannian geometry, Providence, RI: AMS...

{\displaystyle \partial _{z}X^{\mu }-i{\overline {\theta _{L}}}\Gamma ^{\mu }\partial _{z}\theta _{L}-i{\overline {\theta _{R}}}\Gamma ^{\mu }\partial _{z}\theta...